sudo执行shell中自定义函数
#!/bin/bash
function me()
{
echo "im $(whoami) "
}
Test that it works.
me
sudo -u test whoami
sudo -u test me
FUNC=$(declare -f me)
sudo -u test bash -c "$FUNC; me"
me
#sudo -u test bash -c "$(declare -f me); me"
[root@server ~]# ./test.sh
im root
test
sudo: me: command not found
im test
im root
